MGCCC, Perk Learning Lab
TLM
1 mol = 6.022 x 1023 particles
1 mol = 6.022 x 1023 atoms (use with molecular compounds)
1 mol = 6.022 x 1023 formula units (used with ionic compounds)
1 mol = 6.022 x 1023 molecules
Atom- the smallest particle of an element that maintains its chemical identity through all chemical and physical changes.
Molecule- the smallest particle of an element or compound that can have a stable independent existence
Element- a substance that cannot be decomposed into simpler substances by chemical means; composed of only one type of atom
Ion- an atom or group of atoms that carries an electrical charge; unequal # of protons and electrons
Molecular Compound- a compound that does not contain ions
Ionic Compound- a compound that is composed of cations and anions
|
Element |
#
of Atoms in formula |
Sample |
Contains |
|
Carbon: C |
1 atom for each molecule |
12.001g C |
6.022 x 1023 C atoms or 1 mol of C atoms 6.022 x 1023 C molecules |
|
Hydrogen: H2 |
2 atoms for each molecule |
1.0079g H2 |
6.022 x 1023 H atoms or 1 mol of H atoms 3.011 x 1023 H2 molecules |
|
Sulfur: S8 |
8 atoms for each molecule |
32.066g S8 |
6.022 x 1023 S atoms or 1 mol of S atoms 0.75 x 1023 S8 molecules |
|
Substance |
Molecular
Wt |
Sample |
#
of Atoms in formula |
Contains |
Hydrogen
|
2.016 |
2.016g H2 |
2 H |
6.022 x 1023 molecules or 1 mol of H2 molecules 2 * 6.022 x 1023 = 1.2044 x 1024 atoms of H or 2 mol of H atoms |
|
Methane |
16.04 |
16.04g CH4 |
1 C, 4 H |
6.022 x 1023 CH4 molecules or 1 mol of CH4 molecules 6.022 x 1023 C atoms or 1 mol of C atoms 4 * 6.022 x 1023 = 2.4088 x 10 23 H atoms or 4 mol of H atoms |
|
Compound |
Formula
Wt |
Sample
with a Mass of 1 mol |
#
of Atoms in formula |
Contains |
|
Sodium Chloride |
58.44 |
58.44 g NaCl |
1 Na, 1 Cl |
6.022 x 1023 Na+ ions or 1 mol of Na+ ions 6.022 x 1023 Cl- ions or 1 mol of Cl- ions |
|
Aluminum Sulfate |
342.1 |
342.1g Al2(SO4)3 |
2 Al, 3 (SO4) |
2 * 6.022 x 1023= 1.2044 x 1024 Al+3 ions or 2 moles of Al+3 ions 3 * 6.022 x 1023= 1.8066 x 1024 SO4-2 ions or 3 moles of SO4–2 ions |
MGCCC, Perk Learning Lab
TLM
1. How many moles of atoms does 355.7 g of gold contain?
2. Calculate the mass of one carbon atom in grams.
3. How many (a) moles of Cl2 (b) Cl2 molecules and (c) Cl atoms are contained in 45 g of Chlorine gas (Cl2)?
4. Calculate the number of (a) hydrogen, (b) oxygen and (c) sulfur atoms in 63g of sulfuric acid (H2SO4)
6. How many moles of O are in 6 moles of O3?
ANSWERS
1. 355.7g Au * 1 mol Au atoms = 1.805 moles of Au atoms
196.97 g Au
2. 12 g C * 1 mol C atoms = 1.99 x 10-23 g C/ C atoms
1 mol C atoms 6.022 x 10 23 C atoms
3. a. 45g Cl2 * 1 mol Cl2 = 0.635 mol Cl2
70.906 g Cl2
b. 0.635 mol Cl2 * 6.022 x 1023 molecules = 3.82 x 1023 Cl2 molecules
1 mol Cl2
c. 3.82 x 1023 Cl2 molecules * 2 Cl atoms = 7.64 x 1023 Cl atoms
1 Cl2 molecule
4. a. 63 g H2SO4 * 1 mol H2SO4 * 6.022 x 1023 molecules * 2 H atoms = 7.7 x 1023 H atoms
98 g H2SO4 1 mol H2SO4 1 H2SO4 molecule
b. 63 g H2SO4 * 1 mol H2SO4 * 6.022 x 1023 molecules * 1 S atom = 3.87 x 1023 S atoms
98 g H2SO4 1 mol H2SO4 1 H2SO4 molecule
c. 63 g H2SO4 * 1 mol H2SO4 * 6.022 x 1023 molecules * 4 O atoms = 1.54 x 1024 O atoms
98 g H2SO4 1 mol H2SO4 1 H2SO4 molecule
5. a. 2.516 x 1023 atoms * 1 mol = 0.4178 mol of metal
6.022 x 1023 atoms
b. 82.29 g = 196.96 g/mol , Au (gold) is the metal
0.4178 mol
6. 6 mol O3 * 3 mol O = 18 mol O
1 mol O3