Perk Learning Lab, MGCCC
GENERAL
CHEMISTRY, 5th ed., Whitten,
Davis & Peck
Chapter 5 Review Quiz
a. alpha particle l. group
b. anode m. Heisenberg uncertainty principle
c. atomic number n. Hund’s rule
d. canal ray o. Isotopes
e. cathode ray p. Mass number
f. continuous spectrum q. neutron
g. diamagnetism r. nucleus
h. electromagnetic radiation s. Pauli Exclusion Principal
i. electron t. period
j. ferromagnetism u. photon
k. frequency v. proton
w. paramagnetism
x. wavelength
_____1. a packet of light or electromagnetic radiation; quantum of light
_____2. energy that is propagated by means of electric and magnetic fields that oscillate
in directions perpendicular to the direction of travel of the energy.
_____3. a vertical column in the periodic table; also called a family
_____4. the integral number of protons in the nucleus defines the identity if an element
_____5. No two electrons in the same atom may have identical sets of four quantum
numbers.
_____6. positive electrode
_____7. a subatomic particle having a mass of 1.0073 amu and a charge of +1, found in
nucleus of atom.
_____8. beam of electrons going from a negative electrode toward the positive electrode
in a cathode ray tube.
_____9. weak repulsion by a magnetic field
_____10. two or more forms of the same atom of the same element with different masses;
same number of protons, different number of neutrons.
11. Estimate the total mass of a 13154Xe atom that is due to a) electrons, b) protons, and c) neutrons.
12. Determine the number of protons, neutrons and electrons in each of the following species:
a) 12753I –1 b) 5626 Fe+3 c) 2412Mg
13. What is the symbol of the species composed of each of the following subatomic particles? a) 48 protons, 64 neutrons, 47 electrons
b) 35 protons, 45 neutrons, 36 electrons
c) 20 protons, 20 neutrons, 20 electrons
14. Calculate the atomic weight of chromium using the following data: 4.35% 50Cr (49.9461 amu); 83.79% 52Cr (51.9405 amu); 9.50% 53Cr (52.9406 amu); 2.36% 54Cr (53.9389 amu).
15. Excited lithium ions emit radiation at a wavelength of 670.8 nm in the visible range of the spectrum. Calculate a) the frequency and b) the energy of a photon of this radiation.
16. If each atom in one mole of atoms emits a photon of wavelength 5.50 x 103 angstrom, how much energy is lost?
17. Hydrogen atoms absorb energy so that the electrons are excited to the energy level n = 6. Electrons then undergo these transitions (1) n = 6 à n = 3, (2) n = 6 à n = 1, and (3) n = 3 à n = 1. Determine the energy, the frequency and the wavelength for each.
18. The following are prominent lines in the visible region of the emission spectra of the elements listed. The lines can be used to identify the elements. What color is the light responsible for each line? a) lithium, 4603 angstrom, b) neon, 540 nm and c) potassium v = 3.9 x 1014 Hz.
19. What is the wavelength corresponding to a neutron of mass 2.3 x 10-27 kg moving at 2536 m/s?
20. What is the velocity of an alpha particle that has a de Broglie wavelength of 0.529 angstrom?
21. An electron is in one of the 4d orbitals. What are the possible values of the quantum numbers n, l, ml an ms for the electron.
22. Give the ground state electron configuration in shorthand for the following elements: a) S b) Cu c) Sr
23. Which elements are represented by the following electron configuration?
a) [Ar]4s23d6
b) 1s22s22p63s23p64s23d104p3
c) [Kr]5s24d105p1
24. Construct a table in which you list a possible set of values for the four quantum numbers for Ni.
1. u
2. h
3. l
4. c
5. s
6. b
7. v
8. e
9. g
10. o
11. Total sum of subatomic particles 131 + 54 + 54 = 239
a) electrons = (54/239) x 100% = 22.6%
b) protons = (54/239) x 100% = 22.6%
c) neutrons = (131/239) x 100% = 54.8%
12. a) protons = 53 b) protons = 26 c) protons = 12
neutrons= 74 neutrons = 30 neutrons = 12
electrons = 54 electrons = 23 electrons = 12
13. a) 11248Cd+1 b) 8035Br-1 c) 4020Ca
14.(0.0435 * 49.9461) + (0.8379 * 51.9405) + (0.095 * 52.9406) + (0.0236 *53.9389)
= 2.172 + 43.521 + 5.029 + 1.273
= 51.995 amu
15. l = 670.8 nm * (1m/109 nm) = 7 x 10-7 m
v = c/l = (3 x 108 m/s) ¸ (7 x 10-7 m) = 4.29 x 1014 /s
E = hv = (6.63 x 10-34 J·s) * (4.29 x 1014 /s) = 2.84 x 10-19 J
16. l = 5.5 x 103 angstrom x ( 1 x 10-10 m/ 1 angstrom)= 5.5 x 10-7 m
v = (3 x 108 m/s) ¸ (5.5 x 10-7 m) = 5.45 x 1014 /s
E = (6.63 x 10-34 J·s) * (5.45 x 1014 /s) = 3.6 x 10-19 J/mol
Ephoton = (3.6 x 10-19 J/mol) * (6.02 x 1023 photons) = 2.17 x 105 J/photon
17. #1) n = 6 à n = 3
1/l = R [1/n12 - 1/n22] = (1.097 x 107 /m) * [1/32 – 1/62]
1/l = (1.097 x 107 /m) * [1/9 – 1/36]
l = 1 ¸ {(1.097 x 107 /m) * [1/9 – 1/36]}
l = 1. 09 x 10-6 m
v = c/l = (3 x 108 m/s) ¸ (1. 09 x 10-6 m) = 2.75 x 1014 /s
E = hv = (6.63 x 10-34 J·s) * (2.75 x 1014 /s) = 1.8 x 10-19 J
17. #2) n = 6 à n = 1
1/l = R [1/n12 - 1/n22] = (1.097 x 107 /m) * [1/12 – 1/62]
l = 1 ¸ {(1.097 x 107 /m) * [1/1 – 1/36]}
l = 9.37 x 10-8 m
v = c/l = (3 x 108 m/s) ¸ (9.37 x 10-8 m) = 3.2 x 1015 /s
E = hv = (6.63 x 10-34 J·s) * (3.2 x 1015 /s) = 2.12 x 10-18 J
#3 n = 3 à n = 1
1/l = R [1/n12 - 1/n22] = (1.097 x 107 /m) * [1/12 – 1/32]
l = 1 ¸ {(1.097 x 107 /m) * [1/1 – 1/9]}
l = 1.025 x 10-7 m
v = c/l = (3 x 108 m/s) ¸ (1.025 x 10-7 m) = 2.92 x 1015 /s
E = hv = (6.63 x 10-34 J·s) * (2.92 x 1015 /s) = 1.94 x 10-18 J
18. a) 4603 angstrom = blue
b) 540 nm * ( 1m/109 nm) * (1 angstrom /1 x 10-10 m) = 5.4 x 103
or 5400 angstrom = yellow
c) l = (3 x 108 m/s) ¸ (3.9 x 1014 /s) = 7.69 x 10-7 m
7.69 x 10-7 m * (1 angstrom /1 x 10-10 m) = 7692 angstrom = red
19. l = (6.63 x 10-34 kg·m2/s) ¸ (2.3 x 10-27 kg) (2536 m/s) = 1.13 x 10-10 m
20. l = 0.529 angstrom * (1 angstrom /1 x 10-10 m) = 5.29 x 10-11 m
m = (4g/1mol He ) * (1 mol He/ 6.02 x 1023 He) * (1 kg/1000g) = 6.65 x 10-27 kg
v = h/ml = (6.63 x 10-34 kg·m2/s) ¸ { (6.65 x 10-27 kg) * (5.29 x 10-11 m)}
= 1.88 x 103 m/s
21. n = 4, l = 2, ml = -2, -1, 0, +1, +2, ms = +1/2 or –1/2
22. a) S= 16 electrons, 1s22s22p63s23p4
b) Cu = 29 electrons, 1s22s22p63s23p64s23d9
c) Sr = 38 electrons, 1s22s22p63s23p64s23d9
23. a) Fe b) As c) In
24.
|
Configuration of electron |
n |
l |
ml |
ms |
|
1s1 |
1 |
0 |
0 |
+ ½ |
|
1s2 |
1 |
0 |
0 |
- ½ |
|
2s1 |
2 |
0 |
0 |
+ ½ |
|
2s2 |
2 |
0 |
0 |
- ½ |
|
2p1 |
2 |
1 |
-1 |
+ ½ |
|
2p2 |
2 |
1 |
0 |
+ ½ |
|
2p3 |
2 |
1 |
+1 |
+ ½ |
|
2p4 |
2 |
1 |
-1 |
- ½ |
|
2p5 |
2 |
1 |
0 |
- ½ |
|
2p6 |
2 |
1 |
+1 |
- ½ |
|
3s1 |
3 |
0 |
0 |
+ ½ |
|
3s2 |
3 |
0 |
0 |
- ½ |
|
3p1 |
3 |
1 |
-1 |
+ ½ |
|
3p2 |
3 |
1 |
0 |
+ ½ |
|
3p3 |
3 |
1 |
+1 |
+ ½ |
|
3p4 |
3 |
1 |
-1 |
- ½ |
|
3p5 |
3 |
1 |
0 |
- ½ |
|
3p6 |
3 |
1 |
+1 |
- ½ |
|
4s1 |
4 |
0 |
0 |
+ ½ |
|
4s2 |
4 |
0 |
0 |
- ½ |
|
3d1 |
3 |
2 |
-2 |
+ ½ |
|
3d2 |
3 |
2 |
-1 |
+ ½ |
|
3d3 |
3 |
2 |
0 |
+ ½ |
|
3d4 |
3 |
2 |
+1 |
+ ½ |
|
3d5 |
3 |
2 |
+2 |
+ ½ |
|
3d6 |
3 |
2 |
-2 |
- ½ |
|
3d7 |
3 |
2 |
-1 |
- ½ |
|
3d8 |
3 |
2 |
0 |
- ½ |